Question

You have 0.672 L of 4.78 M aqueous AlCl3 solution in a glass. If you gently heat the solution until only 0.380 L is left, what is the new molarity of the AlCl3 solution?

Answer 1

8.45 M

Step-by-step explanation:

To solve this problem we need to keep in mind the definition of molarity:

• Molarity = moles / volume

First we calculate the moles of AlCl₃ in 0.672 L of a 4.78 M solution:

• Moles = Molarity * volume

• Moles = 4.78 M * 0.672 L

• Moles = 3.212 moles

Then we calculate the new molarity of the AlCl₃ solution using that number of moles, which remains the same throughout the evaporation process:

• New Molarity = 3.212 moles / 0.380 L

• New Molarity = 8.45 M