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2. Solve the system of equations.

1
ży 22
—1
x + 3y = 2 = 10
11/x + 2
+ z = -4

2. Solve the system of equations. 1 ży 22 —1 x + 3y = 2 = 10 11/x + 2 + z = -4-example-1
User CharleyXIV
by
6.0k points

1 Answer

5 votes

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Answer:

(x, y, z) = (2, 1, -5)

Explanation:

There are numerous equation solvers available on the web. The attached result is from one of them.

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You may find it easier to solve these by hand if you eliminate fractions.

  • 2x -y +z = -2
  • x +3y -z = 10
  • x +0y +2z = -8

The first step is to look to see what you have, then formulate a strategy for getting a solution. Because the equations containing y have opposite coefficients, one of which is -1, we choose to use those to eliminate y. Immediately, we will have two equations in x and z.

If you multiply the first equation by 3 and add that to the second, then you will eliminate y. The third equation already has y eliminated, so you will then have two equations in x and z.

3(2x -y +z) +(x +3y -z) = 3(-2) +(10)

6x -3y +3z +x +3y -z = -6 +10

7x +2z = 4 . . . . [eq4]

Subtracting the third equation from this eliminates z, so you have ...

(7x +2z) -(x +2z) = (4) -(-8)

6x = 12

x = 2

Substituting into the third equation gives ...

2 +2z = -8

2z = -10

z = -5

Then using the first equation, you have ...

y = 2x +z +2 = 2(2) +(-5) +2 = 1

(x, y, z) = (2, 1, -5)

2. Solve the system of equations. 1 ży 22 —1 x + 3y = 2 = 10 11/x + 2 + z = -4-example-1
User Benjamin Autin
by
6.2k points