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1(1)/(9)*4(1)/(2)+(3(1)/(5)-(1)/(3) )

2 Answers

4 votes

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1 (1)/(9) * 4 (1)/(2) + (3 (1)/(5) - (1)/(3) ) = \\


(9 + 1)/(9) * (8 + 1)/(2) + ( (15 + 1)/(5) - (1)/(3) ) = \\


(10)/(9) * (9)/(2) + ( (16 * 3)/(5 * 3) - (1 * 5)/(3 * 5) ) = \\


(9 * 10)/(9 * 2) + ( (48)/(15) - (5)/(15) ) = \\


(10)/(2) +( (48 - 5)/(15) ) = \\


5 + ( (43)/(15) ) = \\


(75)/(15) + (43)/(15) = (118)/(15) \\

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User Lwxted
by
7.7k points
2 votes

Answer:

118/15 or 7.8666666666666666666666666666666666666666666666666666666666666666... decimal

Explanation:

Simplify the following:

(1 + 1/9) (4 + 1/2) + 3 + 1/5 - 1/3

Put 1 + 1/9 over the common denominator 9. 1 + 1/9 = 9/9 + 1/9:

9/9 + 1/9 (4 + 1/2) + 3 + 1/5 - 1/3

9/9 + 1/9 = (9 + 1)/9:

(9 + 1)/9 (4 + 1/2) + 3 + 1/5 - 1/3

9 + 1 = 10:

10/9 (4 + 1/2) + 3 + 1/5 - 1/3

Put 4 + 1/2 over the common denominator 2. 4 + 1/2 = (2×4)/2 + 1/2:

10/9 (2×4)/2 + 1/2 + 3 + 1/5 - 1/3

2×4 = 8:

10/9 (8/2 + 1/2) + 3 + 1/5 - 1/3

8/2 + 1/2 = (8 + 1)/2:

10/9 (8 + 1)/2 + 3 + 1/5 - 1/3

8 + 1 = 9:

10/9×9/2 + 3 + 1/5 - 1/3

10/9×9/2 = (10×9)/(9×2):

(10×9)/(9×2) + 3 + 1/5 - 1/3

(10×9)/(9×2) = 9/9×10/2 = 10/2:

10/2 + 3 + 1/5 - 1/3

The gcd of 10 and 2 is 2, so 10/2 = (2×5)/(2×1) = 2/2×5 = 5:

5 + 3 + 1/5 - 1/3

Put 5 + 3 + 1/5 - 1/3 over the common denominator 15. 5 + 3 + 1/5 - 1/3 = (15×5)/15 + (15×3)/15 + 3/15 - 5/15:

(15×5)/15 + (15×3)/15 + 3/15 - 5/15

15×5 = 75:

75/15 + (15×3)/15 + 3/15 - 5/15

15×3 = 45:

75/15 + 45/15 + 3/15 - 5/15

75/15 + 45/15 + 3/15 - 5/15 = (75 + 45 + 3 - 5)/15:

(75 + 45 + 3 - 5)/15

| 1 |

| 7 | 5

| 4 | 5

+ | | 3

1 | 2 | 3:

(123 - 5)/15

| | 1 | 13

| 1 | 2 | 3

- | | | 5

| 1 | 1 | 8:

Answer: 118/15

User Nghauran
by
7.8k points