Question

What is the equation of a line that is parallel to -x + 3y = 6 and passes through the point (3, 5)?

Answer 1

y = 1/3x + 4

Explanation:

Make it into slope intercept form

3y = x + 6

y = 1/3x + 2

parallel = same slope

y = 1/3x + b, plug in (3,5)

5 = 1/3(3) + b, b = 4

y = 1/3x + 4