Question

During a lab you combined 5g of sodium bicarbonate and 10g of vinegar to produce sodium acetate, water, and carbon dioxide. After the reaction the contents of the beaker only weighed 14.5g. How much of the reactants were converted into carbon dioxide?

Answer 1

Step-by-step explanation:

Na₂CO₃ + CH₃COOH = CH₃COONa + CO₂ + H₂O .

1 mole 1 mole

mol weight of sodium carbonate = 106

mol weight of acetic acid = 60

5 g of sodium carbonate = 5 / 106 = .047 moles

10 g of acetic acid = 10 / 60 = .167 moles

sodium carbonate is the limiting reagent

.047 moles will react with .047 moles of acetic acid to give products .

grams of acetic acid reacted = .047 x 60 = 2.82 gram

grams of sodium carbonate reacted = 5 grams .