Answer:
Distance is 6.7units to the nearest tenth.
Step-by-step explanation:
To solve this problem, we the distance formula. And this is given as:
![D = (|a x + b y + c|)/(√(a^2 + b^2))](https://img.qammunity.org/2021/formulas/mathematics/high-school/7k44vurkjn6a72k0wmwtvu7ipf2idy804w.png)
We were given the equation:
y = 2 x + 4
This can also be rewritten as:
y – 2 x – 4 = 0.
Therefore, a = -2, b = 1 and c = -4
Also, we were given the points:
(x, y) = (–4, 11)
Making use of the above formula for distance, we have:
![D = (|-2* -4 + 1* 11 + -4|)/(√(-2^2 + -4^2))](https://img.qammunity.org/2021/formulas/mathematics/high-school/k3ps0r171roiphjbk21bn1juz8wbh5qmga.png)
![D = (15)/(√(5))](https://img.qammunity.org/2021/formulas/mathematics/high-school/117tye5sngqdpvfm9o1m8b0672o7ju622u.png)
D = 6.7units (to the nearest tenth)