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If (n+1)!=90×(n-1)!,find n.​

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\displaystyle\bf\\(n+1)!=90* (n-1)!\\\\(n-1)!* n*(n+1)=90* (n-1)!~~~\Big|~:(n-1)!\\\\n(n+1)=90\\\\n(n+1)=9*10\\\\n(n+1)=9(9+1)\\\\\implies~~\boxed{\bf n=9}

User Paul Pettengill
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