Answer:
720 m
Step-by-step explanation:
Taking the upward direction as positive
We are given:
Initial vertical velocity of the cannonball = 120 m/s
Vertical acceleration of the cannonball = -10 m/s²
Final velocity of the Cannonball = 0 m/s [at the maximum height, the velocity of the ball will be 0 m/s for a moment]
Maximum height of the ball:
v² - u² = 2as [Third equation of motion]
replacing the variables (s is the maximum height)
(0)² - (120)² = 2(-10)(s)
-14400 = -20s
s = -14400 / -20 [Dividing both sides by -20]
s = 720 m
Hence, the maximum height of the Cannonball fired vertically at a velocity of 120 m/s is 720 m