Question

(NEED HELP PLEASE) A physics student goes to the roof of the school, 24.15 m above the ground, and drops a pumpkin straight down with an initial velocity of 0 m/s. How long does it take for the pumpkin to hit the ground?

Answer 1

t = 2.2 s

Step-by-step explanation:

Given that,

Height of the roof, h = 24.15 m

The initial velocity of the pumpkin, u = 0

We need to find the time taken for the pumpkin to hit the ground. Let the time be t. Using second equation of kinematics to find it as follows :

`h=ut+(1)/(2)at^2`

Here, u = 0 and a = g

`h=(1)/(2)gt^2\\\\t=\sqrt{(2h)/(g)} \\\\t=\sqrt{(2* 24.15)/(9.8)} \\\\t=2.22\ s`

So, it will take 2.22 s for the pumpkin to hit the ground.