Question

Help please!!!!!!!!!

Answer 1

`f\left(0\right)=\left(0\right)^2-4\left(0\right)=0-0=0`

`f\left(1\right)=\left(1\right)^2-4\left(1\right)=1-4=-3`

`f\left(2\right)=\left(2\right)^2-4\left(2\right)=4-8=-4`

`f\left(3\right)=\left(3\right)^2-4\left(3\right)=9-12=-3`

`f\left(4\right)=\left(4\right)^2-4\left(4\right)=16-16=0`

Explanation:

Given the function

`f\left(x\right)=x^2-4x`

Putting x=0 in the equation to find f(0)

`f\left(x\right)=x^2-4x`

`f\left(0\right)=\left(0\right)^2-4\left(0\right)=0-0=0`

Putting x=1 in the equation to find f(1)

`f\left(x\right)=x^2-4x`

`f\left(1\right)=\left(1\right)^2-4\left(1\right)=1-4=-3`

Putting x=2 in the equation to find f(2)

`f\left(x\right)=x^2-4x`

`f\left(2\right)=\left(2\right)^2-4\left(2\right)=4-8=-4`

Putting x=3 in the equation to find f(3)

`f\left(x\right)=x^2-4x`

`f\left(3\right)=\left(3\right)^2-4\left(3\right)=9-12=-3`

Putting x=4 in the equation to find f(4)

`f\left(x\right)=x^2-4x`

`f\left(4\right)=\left(4\right)^2-4\left(4\right)=16-16=0`