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23 votes
23 votes
In triangle PQR,PQ=13 cm ,QR=18 cm and PR = 11 cm. Find the size of the largest angle.

User Sony Khan
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2.7k points

1 Answer

10 votes
10 votes

Answer: ~96.83°

Explanation:

1) It's obvious that the largest angle is the opposite to the largest side.

▪︎ QR = 18 (the largest side)

=> <QPR is the largest angle

2) Cosine Rule:

▪︎ QR^2 = QP^2 + PR^2 - 2*QP*PR*cos(QPR)

▪︎ 18*18 = 13*13 + 11*11 - 2*13*11*cos(QPR)

▪︎ 324 = 169 + 121 - 286*cos(QPR)

▪︎ 34 = -286*cos(QPR)

▪︎ cos(QPR) = -34/286

▪︎ <QPR = arccos(-34/286) = 96.827...°

User Abstrus
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