Question

I need help with this simplify 5/4+4(3/4−1/2)^2

Answer 1

`(5)/(4)+4\left((3)/(4)-(1)/(2)\right)^2 =`

`(3)/(4)-(1)/(2) =(3)/(4)-(2)/(4)=`

`\mathrm{Apply\:the\:fraction\:rule}:\quad (a)/(c)-(b)/(c)=(a-b)/(c)`

`=(3-2)/(4)`

`\mathrm{Subtract\:the\:numbers:}\:3-2=1`

`=(1)/(4)`

`=(5)/(4)+4\cdot (1)/(4)^2`

`\mathrm{Apply\:the\:fraction\:rule}:\quad (a)/(c)^n=(a^n)/(c^n)`

`=(5)/(4)+4\cdot (1)/(16)`

`\mathrm{Apply\:the\:fraction\:rule}:\quad \:a+(b)/(c)=(ac+b)/(c)`

`=(4\cdot (1)/(16)\cdot \:4+5)/(4)`

`\mathrm{Multiply\:the\:numbers:}\:4\cdot \:4=16`

`(16\cdot (1)/(16)+5)/(4) =(6)/(4) =\boxed{(3)/(2)}`

`\mathrm{I\:hope\:that\:I\:helped\:you\:!}`

Answer 2

2 1/4

Explanation:

first do 4*3/4-4*1/2 because of order order of operations.

12/4-4/2=3-2=1

then do 1^2 because you do exponents before addition.

1^2=1*1=1

5/4+1=5/4+4/4=9/4

9/4=2 1/4