Question

The imagine below is the question.
A Function, h(x) is defined as shown

Answer 1

Given function

`\\ \rm\Rrightarrow h(x)=\begin{cases}\sf (1)/(4)x-4,x\leqslant 0\\ \sf(1)/(3)x-3,0< x\leqslant 3\\ \sf (1)/(2)x-2,x\geqslant 4\end{cases}`

Take first one and put 0

`\\ \rm\Rrightarrow h(0)`

`\\ \rm\Rrightarrow {0-4}`

`\\ \rm\Rrightarrow -4`

The graph must contain (0,-4)

Only graph B contains (0,-4). so

• Graph B is correct