Does someone mind helping me with this problem? Thank you!

Question 1

Question 2

$(10-(3 \cdot 2^2 - 23))/((1 + 10^2)-2^2 \cdot 5^2) =$

$10-\left(3\cdot \:2^2-23\right) =10-\left(-11\right) =21$

$\left(1+10^2\right)-2^2\cdot \:5^2 = 101-2^2\cdot \:5^2 = 101-4\cdot \:5^2 =101-4\cdot \:25 =101-100 = 1$

=(21)/(1)

(a)/(1)= a

=21

I hope I helped you!

Question 3

Let's simplify ~

$\qquad \sf  \dashrightarrow \: \frac{10 - (3 * 2 {}^(2) - 23) }{(1 + 10 {}^(2)) - {2}^(2) * {5}^(2) }$

$\qquad \sf  \dashrightarrow \: \frac{10 - (3 * 4{}^{} - 23) }{(1 + 10 0{}^{}) - {4}^{} * {25}^{} }$

$\qquad \sf  \dashrightarrow \: \frac{10 - (12- 23) }{(10 1{}^{}) - {100}^{} }$

$\qquad \sf  \dashrightarrow \: (10 - ( - 11) )/(1)$

$\qquad \sf  \dashrightarrow \: 10 + 11$

$\qquad \sf  \dashrightarrow \: 21$