Question

BD bisects LABC. Solve for x and find m2ABC. m_ABD = 4x-2, mZCBD=2x + 6​

Answer 1

i) x = 4°

ii) <ABC = 28°

Explanation:

Given that BD bisects <ABC then it is true to say that;

Angle m < ABD=m < CBD

Hence;

4x-2 = 2x +6

4x-2x = 6 +2

2x = 8

x=8/2 = 4

x= 4°

Hence

Angle m< ABD = 4x-2 = 4*4 -2 = 16-2 =14°

Angle m < ABC = 2* 14° = 28°