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Solve and state any extraneous solutions

Solve and state any extraneous solutions-example-1
User Raxit
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1 Answer

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(3x)/(x - 1) + 2 = (3)/(x - 1)


(3x)/(x - 1) + (2(x - 1) )/( x - 1) = (3)/(x - 1)


(3x)/(x - 1) + (2x - 2)/( x - 1) = (3)/(x - 1)


(3x + 2x - 2)/( x - 1) = (3)/(x - 1)


3x + 2x - 2 = 3


5x - 2 = 3


5x = 3 + 2


5x = 5


x = (5)/(5)


x = 1

User Dmitrii Cheremisin
by
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