Question

Hi. Please I need help with these questions.

It's urgent . 50pts.
No jokes. This time
Answer No 12 and 13

Answer 1

Q 12 roots of the equation

`2x^(2) -6+1=0 \\= (x-(√(10) )/(2))(x+(√(10) )/(2))\\`

∝ =
`(√(10) )/(2)`

β =
`-(√(10) )/(2)`

no matter if u oppose the root

(i) 2(
`(√(10) )/(2)`)
`(-(√(10) )/(2) )^(2)`+2
`((√(10) )/(2) )^(2)`(
`-(√(10) )/(2)`)+2(

(ii)(
`((√(10) )/(2))^(2)` - 3 (
`(√(10) )/(2)`)(
`-(√(10) )/(2)`) + (
`(-(√(10) )/(2))^(2)`) =
`(25)/(2)`

Q 13 roots of equation

`4x^(2) -3x-4=0\\\alpha = -0.693\\\beta = 1.443`

the roots of the second equation are

x1 = 1/3(-0.693) = -0.231

x2 = 1/3(1.443) = 0.481

the equation is

(x+0.231)(x-0.481)=0

`x^(2)-(1)/(4) x-(1)/(9)`