Question

Please Please PLEASE help me

How do I solve this using the quadratic formula? −6x^2−2−3x=−8
Could you also show your work?

Thanks

Answer 1

`x=(-1)/(4) +/-(1)/(4)√(17)`

Explanation:

First, we need to get the equation into the polynomial form. Add 8 to both sides:

`-6x^(2) -2-3x=-8`

`-6x^(2) +6-3x=0`

Rearrange the equation so that it is in standard form:

`-6x^(2) -3x+6=0`

Remember the quadratic formula:

`\frac{-b+/-\sqrt{b^(2)-4ac} }{2a}`

`a`,
`b`, and
`c` are the coefficients of the problem when it is in standard form. In this case,
`a=-6`,
`b=-3`, and
`c=6`. Now, all we need to do is plug those into the quadratic formula.

`\frac{-(-3)+/-\sqrt{(-3)^(2)-4(-6)(6)} }{2(-6)}`

Simplify:

`(3+/-√(153))/(-12)`

`x=(-1)/(4) +/-(1)/(4)√(17)`

Hope this helps!