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25 votes
25 votes
Water has a specific heat of 4.186J/gC how much heat is required to increase 10.0g of water from 25.0C to 30.0C

User John Karasinski
by
2.8k points

1 Answer

12 votes
12 votes

Answer:

Heat = 209.3 J

Step-by-step explanation:

Givens

  • Specific Heat 4.186 J/g °C
  • 10 grams
  • delta t = 30 - 25
  • delta t = 5°C
  • Delta H = ?

Formula

Heat = m c delta t

Solution and Answer

Heat = 10 grams * 4.186 * 5

Heat = 209.3 J

User Robrich
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3.0k points