Answer:
we conclude that the only option (a) is true.
Explanation:
As we know that the multiples of 5 are the numbers which we get when we multiply by 5.
i.e.
5×1=5
5×2=10
Here, 5 and 10 are multiples of 5.
Let p and q are integers that are multiples of 5.
Let us consider
p=5
q=10
so
p+q=5+10
= 15
A number is divisible by 5 if it ends in 5 or 0.
i.e. 15/5 = 3
so p+q is divisible by 3 as there is no remainder left.
Therefore, option (a) is true.
Checking the other options:
(b) P –q is divisible by 10
As
p=5
q=10
so
p-q=5-10
= -5
Numbers that are divisible by 10 need to be even or divisible by 2 and divisible by 5.
As -5 is not divisible by 2.
So, option b is NOT true.
(c) P +q is divisible by 20
As
p=5
q=10
so
p-q=5+10
= 15
Divisibility rule of 20 implies that the last two digits of the number are either 00 or divisible by 20 .
Therefore, P + q= 20 is not divisible by 20 as we don't get the whole number.
(d) P + q is divisible by 25
As
p=5
q=10
so
p-q=5+10
= 15
p+q=15 is not divisible by 25 as it does not end with 00, 25, 50, or 75.
so, option d is NOT correct.
Therefore, we conclude that the only option (a) is true.