Question

A car slows from 37.3 m/s to 8.8 m/s with a constant acceleration of -3.3 m/s2. How long in seconds does it require?

Answer 1

The time it takes the car to stop is 8.64 s.

Step-by-step explanation:

Given;

initial velocity of the car, u = 37.3 m/s

final velocity of the car, v = 8.8 m/s

constant acceleration of the car, a = -3.3 m/s²

The time it takes the car to stop is given by;

`t = (v-u)/(a)`

Substitute the givens;

`t = (v-u)/(a)\\\\t = (8.8-37.3)/(-3.3)\\\\t = 8.64 \ s`

Therefore, the time it takes the car to stop is 8.64 s.