Question

A radio wave transmits 38.5 W/m2 of power per unit area. A flat surface of area A is perpendicular to the direction of propagation of the wave. Assuming the surface is a perfect absorber, calculate the radiation pressure on it.

Answer 1

`P=2.57* 10^(-7)\ N/m^2`

Step-by-step explanation:

Given that,

A radio wave transmits 38.5 W/m² of power per unit area.

A flat surface of area A is perpendicular to the direction of propagation of the wave.

We need to find the radiation pressure on it. It is given by the formula as follows :

`P=(2I)/(c)`

Where

c is speed of light

Putting all the values, we get :

`P=(2* 38.5)/(3* 10^8)\\\\=2.57* 10^(-7)\ N/m^2`

So, the radiation pressure is
`2.57* 10^(-7)\ N/m^2`.