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the velocity of a falling body varies directly as the time of flight if the velocity of the falling body at the end of two seconds is 64.4ft/s find the velocity at the end of 5 seconds

User Yatul
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1 Answer

4 votes

Answer:

Explanation:

If the velocity of a falling body varies directly as the time of flight, this is expressed as;

v α t

v = kt

k = v/t

If at t = 2secs, v = 64.4ft/s

k = 64/2

k = 32 ft

To get the velocity at the end of 5 secs, we will say;

at t = 5secs v = ?

From the formula;

v = kt

v = 32(5)

v = 160ft/s

Hence the required velocity is 160ft/s

User Roco
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