Answer:
1) 1.04 M
2) 4.02 M
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Step-by-step explanation:
Part 1:
We are given:
Number of Moles (n) = 0.65 moles
Volume of Solution (V) = 1.6 L
Solving for the Molarity:
We know that:
Molarity = nV
(where n is the number of moles and V is the volume of the solution in L)
replacing the variables
Molarity = 0.65 * 1.6
Molarity = 1.04 M
Hence, the Molarity is 1.04 M
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Part 2:
We are given:
Volume of Solution = 825 mL OR 0.825 L
Mass of MgS = 28.7 grams
Number of Moles of MgS:
Number of moles = Given mass / Molar mass
Number of Moles = 28.7 / 56.38 [molar mass of MgS = 56.38 g/mol]
Number of Moles = 0.51 moles
Molarity of the Given solution:
We know that:
Molarity = nV
[where n is the number of moles and V is the volume of the solution in L]
replacing the variables
Molarity = 0.51 * 0.825
Molarity = 0.42 M
Hence, the molarity is 0.42 M