x^4 - 6x^2 - 27
Let u = x^2
We know that x^4 = (x^2)^2.
u^2 - 6u - 27
(u - 9)(u + 3)
Now, back-substitite for u.
(x^2 - 9)(x^2 + 3)
The RIGHT SIDE FACTOR is the difference of two squares.
So, x^2 - 9 becomes (x - 3)(x + 3).
(x - 3)(x + 3)^2
Done.
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