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Find the 7th term of the geometric sequence whose common ratio is 2/3 and whose first term is 4

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1 Answer

13 votes

Answer:


a_(7)=(256)/(729) or
a_(7)=0.35

Explanation:


a_(n) =a_(1)* r^(n-1)


a_(7)=4*(2)/(3)^(7-1)


a_(7)=4*(2)/(3)^(6)


a_(7)=4*(64)/(729)


a_(7)=(256)/(729)

or


a_(7)=0.35

User Bhadresh Kathiriya
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