Question

What is the equation of aline that passes through the point (4,-8) and has a slope of -1/2?

Answer 1

The equation of the line will be:

`y=-(1)/(2)x-6`

Explanation:

Given

• slope = m = -1/2

• point (4, -8)

Point slope form:

`y-y_1=m\left(x-x_1\right)`

substituting the values m = -1/2 and the point (4,-8)

`y-\left(-8\right)=(-1)/(2)\left(x-4\right)`

`y+8=(-1)/(2)\left(x-4\right)`

subtract 8 from both sides

`y+8-8=(-1)/(2)\left(x-4\right)-8`

`y=-(1)/(2)x-6`

Therefore, the equation of the line will be:

`y=-(1)/(2)x-6`