Question

How many grams of aluminium chloride are produced when 123.2g of chlorine react with aluminium

Answer 1

Mass = 154.67 g

Step-by-step explanation:

Given data:

Mass of aluminum chloride produced = ?

Mass of chlorine = 123.2 g

Solution:

Chemical equation:

2Al + 3Cl₂ → 2AlCl₃

Number of moles of chlorine:

Number of moles = mass/molar mass

Number of moles = 123.2 g/ 71 g/mol

Number of moles =1.74 mol

Now we will compare the moles of aluminum chloride and chlorine.

Cl₂ : AlCl₃

3 : 2

1.74 : 2/3×1.74 = 1.16 mol

Mass of AlCl₃:

Mass = number of moles × molar mass

Mass = 1.16 mol × 133.34 g/mol

Mass = 154.67 g