Question

A beaker contains 318 mL

m
L
of a 5.75 M
M
HCl(aq)
H
C
l
(
a
q
)
solution. Determine the new concentration of the solution after it is diluted by adding 143 mL
m
L
of water to the beaker.

Answer 1

3.97 M

Step-by-step explanation:

Given data:

Initial volume V₁ = 318 mL

Initial molarity M₁ = 5.75 M

New volume V₂= 461 mL

New concentration M₂= ?

Solution:

New volume V₂= 143 mL+ 318 mL

New volume V₂= 461 mL

Formula:

M₁V₁ = M₂V₂

M₂ = M₁V₁ / V₂

M₂ = 5.75 M × 318 mL / 461 mL

M₂ = 1828.5 M. mL/ 461 mL

M₂ = 3.97 M