Question

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Nitrogen gas can be prepared by passing ammonia over copper(II) oxide, and the other products are copper metal and water vapor. If a sample containing 3.58 moles of NH₃ is reacted with excess copper(II) oxide, how many grams of N₂ will be formed?

Answer 1

Mass of N₂ will be formed : 50.12 g

Further explanation

Reaction

2 NH₃(g) + 3 CuO(s) → N₂(g) + 3 Cu(s) + 3 H₂O(g)

moles NH₃ = 3.58

ratio mol NH₃ : mol N₂ = 2 : 1

so mol N₂ :

`\tt (1)/(2)* 3.58=1.79`

mass N₂ (MW=28 g/mol) :

`\tt 1.79* 28=50.12~g`