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Calculate the Molarity when a 6.11 mL solution of 0.1 H2SO4 is diluted with 105.12 mL of water

User Kimberli
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1 Answer

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Molarity after dilution : 0.0058 M

Further explanation

The number of moles before and after dilution is the same

The dilution formula

M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution

V₁ = volume of the solution before dilution

M₂ = Molarity of the solution after dilution

V₂ = Molarity volume of the solution after dilution

M₁=0.1 M

V₁=6.11

V₂=105.12


\tt M_2=(M_1.V_1)/(V_2)=(0.1* 6.11)/(105.12)=0.0058~M

User Dark Sorrow
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