187k views
1 vote
PLEASE HELP ME THIS IS DUE IN TWO HOURS! :(

The length of Rectangle 1 is 3.2 x 10^5 m. The width of Rectangle 1 is 1.6 x 10^4 m. What is the area of Rectangle 1? Write the answer in Scientific Notation.


Find the area of Rectangle 2 if its length is 1.28 x 10^7 m and its width is 8 x 10^3 m. Write the answer in Scientific Notation.


How many times larger is the area of Rectangle 2 than the area of Rectangle 1? Write the answer in Scientific Notation.


How many times larger is the area of Rectangle 2 than the area of Rectangle 1? Write the answer in Standard Form: __________ times larger

User Hearns
by
7.7k points

1 Answer

5 votes

Answer:

2.0 x
10^(1)

Explanation:

1. length = 3.2 x
10^(5) m

width = 1.6 x
10^(4) m

Area of a rectangle = length x width

= (3.2 x
10^(5)) x (1.6 x
10^(4))

= 5.12 x
10^(9)
m^(2)

2. length = 1.28 x
10^(7) m

width = 8 x
10^(3) m

Area of a rectangle = length x width

= (1.28 x
10^(7)) x (8 x
10^(3))

= 1.024 x
10^(11)
m^(2)


(Area of rectangle 2)/(Area of rectangle 1) =
(1.024*10^(11) )/(5.12*10^(9) )

= 20

= 2.0 x
10^(1)

Thus,

The area of rectangle 2 is 2.0 x
10^(1) times greater than the area of rectangle 1.

User Deinocheirus
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories