Question

The lager of two numbers is 15 more than three times the smaller.If the sum of the two numbers is 63,find the numbers

Answer 1

the numbers are 51 and 12.
x = 3y + 15
51 = (3 x 12) + 15
51 + 12 = 63

Answer 2

The numbers are:

• The smaller number = 12

• The larger number = 51

Explanation:

Let 'x' be the smaller number

As the lager of two numbers is 15 more than three times the smaller. so,

The larger number = 3x+15

As the sum of the two numbers is 63, so the equation becomes

`x + 3x + 15 = 63`

`x+3x=63-15`

`4x=48`

Divide both sides of the equation by

`(4x)/(4)=(48)/(4)`

`x = 12`

Therefore,

The smaller number = x = 12

The larger number = 3x+15 = 3(12) + 15 = 36+15 = 51

Hence, the numbers are:

• The smaller number = 12

• The larger number = 51