Question

At equilibrium, the value of [H ] in a 0.240M solution of an unknown acid is 0.00417M . Determine the degree of ionization and the Ka of this acid.

Answer 1

`ionization=1.74\%`

Step-by-step explanation:

Hello!

In this case, since the degree of ionization of an acid is computed in terms of the concentration of hydrogen ions and the initial concentration of the acid:

`ionization=([H^+])/([HA]) *100\%`

Because the ionization reaction is represented by:

`HA\rightleftharpoons H^++A^-`

Therefore, the degree or percent ionization turns out:

`ionization=(0.00417M)/(0.240M) *100\%\\\\ionization=1.74\%`

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