Question

Help please!!!

12x + 6y= 162
2x + 10y= 126

Solve using system of equations. Show all work

Answer 1

x = 8 and y = 11

Explanation:

solve for y

12x + 6y = 162

-12x -12x

6y = 162 - 12x

/6 /6

y = 27 - 2x

substitute

2x + 10(y) = 126

2x + 10(27 - 2x) = 126

2x + 270 - 20x = 126

-18x + 270 = 126

-270 -270

-18x = -144

-18 -18

x = 8

substitute again:

y = 27 - 2(x)

y = 27 - 2(8)

y = 27 - 16

y = 11

Answer 2

(8, 11)

General Formulas and Concepts:

Pre-Algebra

• Order of Operations: BPEMDAS
• Equality Properties

Algebra I

• Solving systems of equations using substitution/elimination

Explanation:

Step 1: Define systems

12x + 6y = 162

2x + 10y = 126

Step 2: Simplify systems

2x + y = 27

x + 5y = 63

Step 3: Rewrite systems

2x + y = 27

x = 63 - 5y

Step 4: Solve for y

1. Substitute in x: 2(63 - 5y) + y = 27
2. Distribute 2: 126 - 10y + y = 27
3. Combine like terms: 126 - 9y = 27
4. Isolate y term: -9y = -99
5. Isolate y: y = 11

Step 5: Solve for x

1. Define equation: x + 5y = 63
2. Substitute in y: x + 5(11) = 63
3. Multiply: x + 55 = 63
4. Isolate x: x = 8