Question

just solve these 2 its prob easy i just too lazy to even try or think at the moment, want to go to bed...​

Answer 1

The correct option is 'No Solution'.

Explanation:

Given the system of the equations

`y=(1)/(2)x-1`

`2x-4y=12`

solving the system of the equations

`\begin{bmatrix}y=(1)/(2)x-1\\ 2x-4y=12\end{bmatrix}`

`\mathrm{Subsititute\:}y=(1)/(2)x-1`

`\begin{bmatrix}2x-4\left((1)/(2)x-1\right)=12\end{bmatrix}`

`2x-4\left((1)/(2)x-1\right)=12`

`2x-2x+4=12`

`4=12`

as

4=12 is false, therefore the system of equations has no solution.

Therefore, the correct option is 'No Solution'.