Displacement of the airplane (s) = 2000 m
Initial velocity of the airplane (u) = 0 m/s (Starts from rest)
Final velocity of the airplane = 56.4 m/s
Equation used to solve the problem:
![\boxed{ \bf{ {v}^(2) = {u}^(2) + 2as}}](https://img.qammunity.org/2021/formulas/physics/college/i66nh7l1pf3u2n6vmqe28ngr162y9zjltj.png)
By substituting values in the equation, we get:
![\rm \longrightarrow {56.4}^(2) = {0}^(2) + 2 * a * 2000 \\ \\ \rm \longrightarrow 3180.96 = 0 + 4000a \\ \\ \rm \longrightarrow 4000a = 3180.96 \\ \\ \rm \longrightarrow (4000a)/(4000) = (3180.96)/(4000) \\ \\ \rm \longrightarrow a = 0.80 \: m {s}^( - 2)](https://img.qammunity.org/2021/formulas/physics/college/oiq0kznhxt9c4lnvsth853ie62ercyd8o2.png)
Minimum uniform acceleration necessary for the plane to take flight (a) = 0.80 m/s²