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The figure is a diagram of a wall. Lengths are given in feet.

Diagram of a wall.


a. How many square feet of wallpaper would be needed to cover the wall? Type the answer in the box below.


square feet






Explain your reasoning.




b. Wallpaper is sold in rolls that are 2 feet wide. What is the minimum length you would need to purchase to cover the wall? Type the answer in the box below.


feet

The figure is a diagram of a wall. Lengths are given in feet. Diagram of a wall. a-example-1
User MartinK
by
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1 Answer

4 votes

Answer:

a. The area of the wall is 60 ft.²

b. The minimum length of wallpaper to be purchased is 30 ft

Explanation:

a. The given diagram is a pentagon, with the two vertical sides equal in length and the two slant sides equal in length and one horizontal

The length of the vertical sides = 6 feet each

The length of the horizontal side = 8 feet

The height of the pentagon = 9 feet

The pentagon can be split into a rectangle with a triangular cap by an horizontal line drawn at point of intersection of the vertical sides and the horizontal sides

The area of the formed rectangle = Base × Height of rectangle

∴ The area of the formed rectangle = 6 × 8 = 48 ft.²

The area of the triangular part of the figure = 1/2 × base × Height of triangle

a = 9 - 6 = 3 feet

∴ The area of the triangular part of the figure = 1/2 × 8 × 3 = 12 ft.²

The area of the wall = The area of the formed rectangle + The area of the triangular part of the figure

∴ The area of the wall = 48 ft.² + 12 ft.² = 60 ft.²

The area of the wall = 60 ft.²

b. The width of the sold wallpaper = 2 feet wide

The area of wallpaper = Length of wallpaper × The width of the sold wallpaper

The area of wallpaper required = The area of the wall = 60 ft.²

∴ 60 ft.² = Length of wallpaper × 2 ft.

Length of wallpaper = 60 ft.²/2 ft. = 30 ft.

The minimum length of wallpaper to be purchased = 30 ft.

User Ssast
by
5.6k points