Question

Use the function y=3/2x +3 to
complete the table of values.

Answer 1

Please check the explanation.

Explanation:

Given the function

`y=(3)/(2)x\:+3`

• Putting all the values of y=9, 6, 0, and -3 to complete the table

FOR y=9

`y=(3)/(2)x\:+3`

putting y=9

`9=(3)/(2)x+3`

switch sides

`(3)/(2)x+3=9`

subtract 3 from both sides

`(3)/(2)x+3-3=9-3`

`(3)/(2)x=6`

`3x=12`

`x=4`

Hence,

when y=9, x=4

FOR y=6

`y=(3)/(2)x\:+3`

putting y=6

`6=(3)/(2)x+3`

switch sides

`(3)/(2)x+3=6`

subtract 3 from both sides

`(3)/(2)x+3-3=6-3`

`(3)/(2)x=3`

`3x=6`

`x=2`

Hence,

when y=6, x=2

FOR y=0

`y=(3)/(2)x\:+3`

putting y=0

`0=(3)/(2)x+3`

switch sides

`(3)/(2)x+3=0`

subtract 3 from both sides

`(3)/(2)x+3-3=0-3`

`(3)/(2)x=-3`

`3x=-6`

`x=-2`

Hence,

when y=0, x=-2

FOR y=-3

`y=(3)/(2)x\:+3`

putting y=-3

`-3=(3)/(2)x+3`

switch sides

`(3)/(2)x+3=-3`

subtract 3 from both sides

`(3)/(2)x+3-3=-3-3`

`(3)/(2)x=-6`

`3x=-12`

`x=-4`

Hence,

when y=-3, x=-4

Hence, the table becomes:

x y

9 4

6 2

0 -2

-3 -4