Question

Determine the mass of CO2 gas produced when 8.24 g of NaHCO3 is added to a solution that contains 4.41 g of HCl.

Answer 1

The mass of CO₂ gas = 4.312 g

Further explanation

Reaction

NaHCO₃ (s) + HCl (aq) → NaCl (aq) + H₂O (aq) + CO₂ (g)

Find limiting reactant

mol NaHCO₃

`\tt (8.24)/(84,007 )=0.098`

mol HCl

`\tt (4.41)/(36.5)=0.121`

Limiting reactant : NaHCO₃ (smaller)

mol CO₂ = mol NaHCO₃ = 0.098

mass CO₂ :

`\tt 0.098* 44=4.312~g`