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If a ship travels north for 18 miles and east for 12 miles,

to the nearest tenth, approximately how far away is it
from it's starting point?

If a ship travels north for 18 miles and east for 12 miles, to the nearest tenth, approximately-example-1
User Deshg
by
5.1k points

1 Answer

6 votes

Answer:

The ship is approximately 21.6 miles away from its starting point

Explanation:

∵ The North and the East are perpendicular

→ That means the distance between the starting position and

the ending position shows a hypotenuse of a right triangle which

its legs are the distances due to North and East

∵ The ship travels north for 18 miles

leg1 = 18 miles

∵ The ship travels east for 12 miles

leg2 = 12 miles

→ By using Pythagoras Theorem

(hypotenuse)² = (leg1)² + (leg2)²

∴ (hypotenuse)² = (18)² + (12)²

∴ (hypotenuse)² = 324 + 144

∴ (hypotenuse)² = 468

→ Take √ for both sides

∴ hypotenuse = 21.63330765

→ Approximate it to the nearest tenth

hypotenuse = 21.6 miles

∵ The hypotenuse of the right triangle represents the distance from

the starting position to the ending position

The ship is approximately 21.6 miles away from its starting point

User Colin Ji
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