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A: UT= 104 m B: UT=104 m C: UT=112m D: UT=126m

A: UT= 104 m B: UT=104 m C: UT=112m D: UT=126m-example-1

2 Answers

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Final answer:

The question relates to the subject of Physics and involves concepts such as displacement, velocity, and time. These are topics typically covered in a High School physics curriculum.

Step-by-step explanation:

The question provided seems to involve physical quantities like distance, velocity, and time, suggesting that it is related to the subject of Physics. The values given reference displacement (in meters), speeds (in meters per second), and time (in seconds), which are all common physical concepts typically covered in high school curriculum. The presence of scientific notation and references to displacement and velocity indicates concepts from a high school level or introductory college level physics course.

Specifically, the use of 'UT' might refer to 'initial velocity times time' in the context of kinematic equations. The example provided with a bullet's velocity and traverse time further suggests kinematic calculations, which are part of the study of mechanics in physics. The notations and calculations are consistent with those used in physics for describing motion.

User Evgeni Nabokov
by
5.5k points
3 votes

Answer:

m∠R = 126° and UT = 104

Step-by-step explanation:

In the given triangles, two angles and one side is congruent so using ASA postulate both triangles are congruent.

IT can be written as:

ΔQRS = ΔTUV

When two triangles are congruent their respective sides and angles are congruent

So,

m∠R ≅ m∠U

And

UT = RQ

Using these

m∠R ≅ m∠U


10y-14 = 5y+56\\10y-5y-14 = 56\\5y = 56+14\\5y = 70\\(5y)/(5) = (70)/(5)\\y = 14

Putting y = 14 in 10y-14


10(14)-14\\= 140-14\\= 126

Hence,

m∠R = 126°

And

RQ = UT


14x-36 = 2x+84\\14x-2x-36 = 84\\12x = 84+36\\12x = 120\\(12x)/(12) = (120)/(12)\\x = 10

Putting x = 10 in 2x+84


2(10)+84\\=20+84\\=104

Hence,

m∠R = 126° and UT = 104

User Brkeyal
by
4.6k points
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