Question

A gas occupies a 40.0 mL at 50 K. What volume does it occupy at 300K?

A. 182 mL

B. 240 mL

C. 400 mL

D. 424 mL

Answer 1

B

Step-by-step explanation:

Recall the ideal gas law:

`\displaystyle PV = nRT`

Because pressure and amount is kept constant while volume and temperature changes, we can rearrange the formula as:

`\displaystyle (V)/(T) = (nR)/(P)`

The right-hand side is simply some constant. In other words:

`\displaystyle (V_1)/(T_1)= (nR)/(P) = (V_2)/(T_2)`

Substitute in known values and solve:

`\displaystyle \begin{aligned} \frac{(40.0\text{ mL})}{(50\text{ K})} & = \frac{V_2}{(300\text{ K})}\\ \\ V_2 & =240\text{ mL} \end{aligned}`

In conclusion, our answer is B.