Question

The flagpole in front of VHS 50 feet tall. The angle of elevation from the end of its shadow to the top of the flagpole is 46°. what is the length of the shadow? Round your answer to the nearest foot

Answer 1

The length of the shadow is 48.28 feet.

Explanation:

The flagpole at its shadow form a 46, 44, 90 triangle.

Let AB be the flagpole. AC is the shadow.

Let's use the sine law to calculate AC.

`(AC)/(sin(44))=(50)/(sin(46))\\AC=\sin(44)*(50)/(sin(46))AC=48.28`