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4)_Slope = 4; contains (-5, - 13)
I need help please

User Bearfriend
by
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1 Answer

4 votes

Answer:

The equation of the line with slope = 4 and point (-5, -13)

will be:


  • y=4x+7

Explanation:

Given

  • slope = m = 4
  • point = (-5, -13)

As the point-slope form of the equation of line is


y-y_1=m\left(x-x_1\right)

where m is the slope.

substituting the values m = 4 and the point (-5, -13)


y-y_1=m\left(x-x_1\right)


y-\left(-13\right)=4\left(x-\left(-5\right)\right)


y+13=4\left(x+5\right)

subtract 13 from both sides


y+13-13=4\left(x+5\right)-13


y=4x+7

Therefore, the equation of the line with slope = 4 and point (-5, -13)

will be:


y=4x+7

User Yuvilio
by
5.3k points