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(dy/dx) - 2xy = x, y(0) = 0, find y(1).​

User Oscarm
by
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1 Answer

2 votes

Answer :

2y=1+e−x2

Solution :

IF=e∫2xdx=ex2

∴y×ex2=∫xex2dx=12∫etdt+C, where x2=t

=12ex2+C.

∴y=12+Cex2

Putting y=1andx=0, we get C=12.

User Kodemi
by
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