Question

Please help me solve this?

Answer 1

12
`x^(4)`y
`z^(7)`√3x

Explanation:

2√108
`x^(9)`y²
`z^(14)`

so you will need two of something to take one out from under the squareroot

we can rewrite
`z^(14) = z^(7) *z^(7)` so we can take a
`z^(7)` out

we can rewrite y² as y*y so we can take a y out

we can rewrite
`x^(9)` as
`x^(4) *x^(4) *x` so we can take a
`x^(4)`out

for 108 think what is the smallest prime number that divides 108 and is 2

108= 2*54

same algorithm, smallest prime number that divides 54 is 2 so

108=2*2*27

same algorithm, smallest prime number that divides 27 is 3 so

108=2*2*3*9

we know 9 is 3*3 so

108=2*2*3*3*3 we can take out one 2 and one 3

put them all toghether now

2*2*3*
`x^(4)`*y*
`z^(7)`√3x = 12
`x^(4)`y
`z^(7)`√3x