Question

If a line has a slope of 4 and contains the point (-2, 5), what is its equation in

point-slope form?
A. y-5= 4(x + 2)
B. y-5= 4(x-2)
OC. y+ 2 = 4(x-5)
OD. y + 5 = 4(x - 2)

Answer 1

B. y-5= 4(x-2)

Explanation:

I'm not sure how to describe it, believe me tho but if my answer is incorrect my fault then.

Answer 2

Answer: A. y - 5 = 4(x + 2)

`\rule{130}{1}`

`\rule{1}{5 } \ \ \sf point \ slope \ form : y-y_1 = m(x - x_1) \quad \ where \ (x_1 , \ y_1)\ are \ points \ \ \ \rule{1}{5}`

Given points: (-2, 5)

solving stepwise:

`\rightarrow y - 5 = 4(x - (-2))`

`\rightarrow y - 5 = 4(x +2) \bf \quad \quad This \ is \ point \ slope \ form`

`\rightarrow y - 5 = 4x + 8`

`\rightarrow y = 4x + 13 \quad \quad \quad \quad \bf This \ is \ slope \ intercept \ form`