If the solutions of p(x) = 0 are -14 and 11, which function could be p?

asked Oct 7, 2021 95.3k views

5 votes

6.2k points

Please log in or register to add a comment.

4 votes

Answer:

p^2+3p-154=0

Explanation:

(p+14)*(p-11)=0

p+14=0

p=-14

p-11=0

p=11

Rents answered Oct 12, 2021

by Rents

6.8k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

6.6m questions

8.8m answers