Question

A) Given that (3x − 1)(x + p) = 3x² +qx-5, find the value of p and q​

Answer 1

Required Answer

• p = 5 ; q = 3(p - 1)

`\dashrightarrow \: \bf{Solution}`

Given that,

`\sf(3x - 1)(x + p) = 3 {x}^(2) + qx - 5`

So yea' let's begin!

`\sf \longrightarrow \sf \: 3 {x}^(2) + 3xp - x - p = 3 {x}^(2) + qx - 5`

Here, 3x² will be cancelled out!

`\sf \longrightarrow \: 3x(p - 1) - p = qx - 5`

`\sf \longrightarrow \: [3(p - 1)]x \: - p = qx - 5`

On comparing ~

`\sf \twoheadrightarrow\bf \: q = \red{3(p - 1)}`

`\bf \twoheadrightarrow \: p = \blue{ 5}`

`\sf`

`\rule{200pt}{2pt}`